AE part 2 (april 5th onwards)-expansion and factorisation

hey sengal-sengal, (form 3 tutors only)!
today i wanna teach ull my second part of AE...
teach them something call..factorisation and expansion...due to HUMAN ERROR, i estimated wrongly on the syllabus, SO, i planned to teach them 20 minutes teach them expansion rules and factoration rules...
but u have to teach them accordingly,
FIRST PART, teach them this thing...this thing ahh...only this thing!!



EXPANSION,1 (a+b)^2--> teach them how to open up (that expression first then only go to the example i show u later) and times remember, show it properly, they might get confused!!
how to teach, like this
**(x+2)(x+5)
=x(x+5)+2(x+5) <--can u see this thing, the x+5 is repeating =x(square) then u expand la! haha 2 (a-b)^2
3 (a+b)(a-b) = (a(square)-b(square)) <-- (remember if factorise, its not equal to (a-b)^2 )

expansion questions pls refer to page 80 (the geetha paper first page) do the right side part...must do with them the third expansion ya, the one the i BOLD and make it big wan.

if u have time, pls go into factorisation, where i teach them based on this levels... hehe

easy moderate hard

FACTORISATION
EASY
two steps--->HCF to pull out the biggest number among the number in the terms
--->pull out the repeated unknowns
u can try this type of question...
8x+32y=8(x+4y) ---> u can see that the HCF of 8 and 32 is 8 =)
5x^2 - 25xy = 5x(x+5y) ---> HCF is 5 then x repeated in two of the terms
...ETC try more

Moderate
example of moderate question are...
ay-az-by+bz = a(y-z)-b(y-z) ---> the main thing is seperate the 4 terms into 2 parts then each part u pull out the repeated unknowns BUT do u discover that the (y-z) is repeated (it must be the SAME!!) refer ** on top...it's similar haha
final answer = (a-b)(y-z)

ab+ac-b^2-bc = a(b+c)-b(b+c)
= (a-b)(b+c)
...etc

HARD
steps 1234 hahaha

S1 pick first term and the third term
s2 do factor for both first and third term
s3 cross multiply to check with the second term
s4 ANSWER is in front of u
(ask LJ for further understanding 017-3817670)

a^2 -6a+9
refer LJ



TERMS = co-efficient x Unknown!!!!!!

by LJ